Question

Calculate the molarity of 30% glucose solution by weight

Answer 1

Answer:

Explanation:

we have 100 g solution. Then in the solution there is 30 g glucose and 70 g water.

Moles of glucose=(30g/180 g/mol)=1/6mol

Moles of water=(70g/18 g/mol)=35/9mol

Total moles

=1/6 mol+35/9 mol=73/18mol

Mile fraction= no. Of miles of glucose ÷ no. Of moles of water + no. Of moles of glucose

Mole fraction of glucose= 1/6 ÷ 73/18

=0.04109