Question

Calculate the molarity of 30% urea (H2N.CO.NH2) solution (w/w). d= 1.04 g/mL.

Answer 1

Answer:

Explanation:

There is 30gm of urea present in aqueous solution in 100ml sol.

Therefore, height of this sol.=vol. of the sol.× density of sol.

=100×1.2=120g

Now mass of the solvent (Water) =

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Answer 2

Answer:

There is 30gm of urea present in aqueous solution in 100ml sol.

Therefore, height of this sol.=vol. of the sol.× density of sol.

=100×1.2=120g

Now mass of the solvent (Water) =120−30=90g

Explanation:

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