Calculate the molarity of 4 mole solution of C3H8O3 with a density of 2g/cm3
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molar mass of C3H803=92 g
molarity = no of moles of solute / vol of Sol in I litre
density = M / v
v = M/ D
volume of 1000g of solution = 1000/2= 500cm³
M =4/500* 1000=8 M
molarity = no of moles of solute / vol of Sol in I litre
density = M / v
v = M/ D
volume of 1000g of solution = 1000/2= 500cm³
M =4/500* 1000=8 M
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Molarity = no. of moles/volume ×100
no. of moles = mass/molar mass
mass= 4×92 (92 is the molar mass)
= 368g
volume = mass / density
volume = 368 / 2 =184 cm^3
Now,
4/184 ×100= 2.2 ( approximately)
no. of moles = mass/molar mass
mass= 4×92 (92 is the molar mass)
= 368g
volume = mass / density
volume = 368 / 2 =184 cm^3
Now,
4/184 ×100= 2.2 ( approximately)
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