Calculate the molarity of 50gm of NaCL dissolve in 500cm cube of solution.
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As Molarity= moles of solute/ volume of solution(liters)
As Molarity= moles of solute/ volume of solution(liters) M= 5.85*1000/((23+35.5)*500)=0.2M
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Given:-
→ Mass of NaCl [solute] = 50 gm
→ Volume of solution = 500 cm³
To find:-
→ Molarity of the solution.
Solution:-
• Molar mass of Sodium (Na) = 23 g/mol
• Molar mass of Chlorine (Cl) = 35.5 g/mol
Hence, molar mass of NaCl :-
= 23 + 35.5
= 58.5 g/mol
Number of mole in 50g of NaCl :-
= Given Mass/Molar mass
= 50/58.5
= 0.855 mole
________________________________
Now, let's convert the volume of the solution from cm³ to L .
⇒ 1 cm³ = 0.001 L
⇒ 500 cm³ = 500(0.001)
⇒ 0.5 L
Molarity of a solution :-
= Moles of solute/Liters of solution
= 0.855/0.5
= 1.71 M
Thus, molarity of the solution is 1.71M .
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