calculate the molarity of 9.8% solution of H2 S o4 if density of the solution is 1.02 gram ml
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Ans would be 1.02 hope u will be able to understand
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Hey there !
Here is your solution :
Density = 1.02 g/ml
Percentage composition = 9.8%
GMM (molar mass) of H₂SO₄ = 98g
Molarity =?
Molarity = percentage composition x density/molar mass
= (98x1.02)/(100x9.8)
= 1.02 M
Therefore, molarity = 1.02M
Hope this helps ya ✌️
Here is your solution :
Density = 1.02 g/ml
Percentage composition = 9.8%
GMM (molar mass) of H₂SO₄ = 98g
Molarity =?
Molarity = percentage composition x density/molar mass
= (98x1.02)/(100x9.8)
= 1.02 M
Therefore, molarity = 1.02M
Hope this helps ya ✌️
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