Question

Calculate the molarity of 9.8% (w/v) h2so4 solution

Answer 1

molarit= no of moles of solute% vol of Sol in litre

Answer 2

The molarity of 9.8% sulfuric acid solution is 0.1M.

Given: 9.8% (w/v) H2SO4 solution.

To find: We have to find the molarity.

Solution:

We know that molarity is a ratio of the number of moles of solute to the total volume of solution.

The molecular mass of sulfuric acid is 98 grams.

Given the mass of sulfuric acid is 9.8 grams.

The number of moles of sulfuric acid is 9.8/98=0.1 mole.

The volume of the solution is 1 litre.

Now the molarity will be-

$\frac{0.1}{1} = 0.1$

The molarity of 9.8% sulfuric acid solution is 0.1 M.