Question

calculate the molarity of a solution containing 4 grams of sodium hydroxide (NaOH) in 100 ml solution​

Answer 1

Answer:

$molarity = \frac{given \: mass}{molecular \: mass} \times \frac{1000}{v(in \: \: l)} \\ = \frac{4}{23 + 16 + 1} \times \frac{1000}{100} \\ = \frac{4 \times 1000}{40 \times 100} \\ = \frac{4}{4} \\ = 1m$