calculate the molarity of a solution containing 5.3 grams of sodium carbonate in 250 ml.
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Explanation:
Answer
Molecular mass of Na
2
CO
3
=106 gmol
−1
∴ Number of moles =
106
53
=0.05mol
As 0.05 mol are dissolved in 500mL;
Number of moles dissolved in 1000mL (1L) or molarity of th solution
=
500
0.05
×1000=0.1M.
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0
Explanation:
molarity=(weight/gram molecular weight)*(1000/volume in ml)
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