Question

Calculate the molarity of a solution containing 9.8g of h2so4 in 200ml solution

Answer 1

Molarity=no of moles /volume of solvent in (l)
Thus molarity=9.8/98×200×10^-3
=0.5
Thus molarity=0.5moles/L

Answer 2

Answer:

The molarity of a solution is 0.5 mol/L.

Explanation:

Mass of sulfuric acid = 9.8 g

Volume of the solution = 200 mL = 0.2 L

Molarity:

$\frac{\text{Mass of}H_2SO_4}{\text{molar mass of}H_2SO_4\times \text{Volume of the solution (L)}}$

$Molarity=\frac{9.8 g}{98 g/mol\times 0.2 L}=0.5 mol/L$

The molarity of a solution is 0.5 mol/L.