Question

Calculate the molarity of a solution of cacl2 if on chemical analysis it is found that 200ml of cacl2 solution contains 3.0
1 into 10 to the power 22 chloride ions

Answer 1

Explanation:

0.125m3.01×10^-22ions

Answer 2

Answer:

12.5M

Explanation:

3.01x10^-22 ions of chloride are present

1 mole = 6.02x10^-23

therefore

moles of Cl- = 5 moles

thus moles of Ca2+ = 2.5 moles

Molarity = moles / litre of solution

= 2.5 / 0.2 = 12.5M