Question

Calculate the molarity of a solution of eth
of ethanol is 0.040 (assume the density​

Answer 1

Explanation:

ANSWER

The mole fraction of ethanol is equal to the ratio of the number of moles of ethanol to the total number of moles present in the solution.

For dilute solutions, 1 L of water (or 1 L of solution) contains

18

1000

=55.55 moles of water.

Let n be the number of moles of ethanol. The mole fraction of ethanol is 0.040.

Hence, 0.040=

n+55.55

n

n=0.040n+2.222

n=

1−0.040

2.222

=2.31 moles.

The molarity of the solution is the ratio of the number of moles of solute present in 1 L of solution.

As 1 L of solution contains 2.31 moles of ethanol, the molarity of a solution is 2.31 M

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Answer 2

Heyo Buddy!

The mole fraction of ethanol is equal to the ratio of the number of moles of ethanol to the total number of moles present in the solution.

For dilute solutions, 1 L of water (or 1 L of solution) contains  

1000 /18 =55.55 moles of water.  

Let n be the number of moles of ethanol. The mole fraction of ethanol is 0.040.

Hence, 0.040=   n/n+55.55

n=0.040n+2.222

n= 2.222 / 1−0.040

​  =2.31 moles.

The molarity of the solution is the ratio of the number of moles of solute present in 1 L of solution.

As 1 L of solution contains 2.31 moles of ethanol, the molarity of a solution is 2.31 M.

Hope the answer was of some help.

:)