calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.40
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2.1 M
Given:
Mass Of Ethanol = 0.04 mole
Moles of Water = 1 - 0.04 = 0.96 mol
Mass Of Water:
= 0.96 * 18
= 17.3 grams
Mass Of Ethanol:
= 0.04 * 46
= 1.84 grams
Total Mass Of The Solution:
= 17.3 + 1.84
= 19.14 grams
Density of water = 1 g/ml assumed
Density = Mass / Volume
=> Volume = Mass / Density
Substituting the values in this formula:
19.1 / 1 = 19.1 mL
Converting to liters:
= 19.1 / 1000
= 0.0191 Liters
Molarity = Mole / Density
Therefore, Molarity:
= 0.04/0.0191
= 2.1 M
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