calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.40
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Answer:
Moles of ethanol= 0.40 mol
Moles of water= 1 - 0.40 = 0.6 mol
Mass of ethanol= 0.40 mol × 46 g/mol = 18.4 g
Mass of water= 0.6 mol × 18 g/mol = 10.8 g
Mass of the solution= 18.4 + 10.8 = 29.2 g
Assuming density of water be 1 g/ml.
Volume of Solution= mass/density = 29.2/1 = 29.2 ml = 0.0292 L
Molarity is the number of moles of solute present in 1 L solution.
Hence,
Molarity of solution= 0.40/0.0292 = 13.6 M
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