Calculate the molarity of a solution that contains 20.0 grams of sodium hydroxide in a 200ml solution.
Answers
Answered by
0
molarity=weight/gram molecular weight×100
NaOH=23+16+1
=40 is gram molecular weight
=20/40×100
=1/2
=0.5×100
=50 is answer obtained
NaOH=23+16+1
=40 is gram molecular weight
=20/40×100
=1/2
=0.5×100
=50 is answer obtained
anubhav2404:
are you sure
yes
check out the answer in ur book
Don't take me wrong but I just checked out on google and I found my explanation seems to be correct
Answered by
0
it can be defined as the number of moles present in a solution. here we have given the mass of sodium hydroxide. as we know the molecular mass of Sodium Hydroxide is 40 u that is the molar mass is 40 gram. and we also know that the number of moles can be found by dividing the given mass by molecular mass so by dividing the given mass by molecular mass we get number of moles 1/2 or 0.5. and now we can find the molarity by dividing the number of moles in the given solution so dividing 0. 5 by 200ml or by 0. 2 litre we get molarity is 2. 5 M
where M is the SI unit of molarity. Equal to gram per cc or gram per litre
Similar questions