Question

Calculate the molarity of a solution when 3.65g of hcl is dissolved in 4L of solution

Answer 1

Answer:

We know, Molarity of a solution is the no. of moles of solute present in 1 L of solution.

Here,

Mass of solute (HCl) = 3.65 g

and molar mass of HCl = 1 + 35.5 = 36.5 units

so,

no. of moles of HCl = given mass/molar mass = 3.65/36.5 = 0.1 mol

Now,

Molarity = 0.1/4 = 0.025 M

I hope you understood :)

Answer 2

Given,

Weight of HCL  = 3.65g

Volume of Solution = 4L

To find,

The Molarity of the solution

Solution,

We can simply solve this numerical problem by using the subsequent process :

Now,

Weight of HCL  = 3.65g

Volume of Solution = 4L

Molarity (M)=?

Molarity (M)= Moles of Solute / Volume of Solution (in Litre)

Molarity (M)= (Weight/Molecular weight) / Volume of Solution (in Litre)

Weight of HCL= 3.65g

Molecular mass of the HCL = Mass of Hydrogen + Mass of Chlorine

Molecular mass of the HCL = 1g + 35.5g

Molecular mass of the HCL = 36.5g

Molarity (M)= (Weight/Molecular mass) / Volume of Solution (in Litre)

Molarity (M)= (3.65g/36.5g) / 4

Molarity (M)= 0.1/4

Molarity (M)= 0.025

Hence, the Molarity (M) of the solution of 3.65g HCl  is 0.025