Chemistry, asked by zahirabaloch110, 3 months ago

Calculate the molarity of a solution which is prepared by dissolving 28.4 g of 3 NaCl in
400 cm^3 of solution.​

Answers

Answered by sm93466
0

Answer:

In order to find the molarity of the solution, you must determine the number of moles of solute present in exactly

1 L

=

10

3

mL

of solution. Notice that you already know the number of milligrams of sodium chloride, the solute, present in

4 mL

of solution, so start by calculating the mass of solute present in

10

3

mL

of solution.

10

3

mL solution

240 mg NaCl

4

mL solution

=

60

10

3

mg

Since

1 g

=

10

3

.

mg

you can say that

10

3

mL

of solution contain

60

10

3

.

mg

=

60

.

g

of sodium chloride. Now, to convert this to moles, use the molar mass of the compound

60

g

1 mole NaCl

58.44

g

=

1.027 moles NaCl

Since this represents the number of moles of sodium chloride present in

10

3

mL

of solution, you can say that the molarity of the solution is equal to

molarity = 1 mol L

1

−−−−−−−−−−−−−−−−−−−

The answer must be rounded to one significant figure, the number of sig figs you have for the volume of the solution.

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