Question

* Calculate the molarity of concentrated nitric acid in a sample which has a denisty
1.41g/ml and the mass percent of nitric acid in it being 69%.​

Answer 1

given: 1.41 g/mL HNO3 solution 

the solution is 69% HNO3 

1. calculate the mass of HNO3 in the solution 

= 1.41 g/ml x 69% 

= 0.9729 g/ml 

2. convert the answer in 1 to mole quantity by dividing it with the molar mass of HNO3 which is 63 g/mol 

= 0.9729 g/ml divided 63 g/mol 

= 0.01544 mol/ml 

3. Since molar quantity is expressed as mole per L, you need to multiply the answer in 2 with 1000 (1L = 1000ml) 

= 0.01544 mol/ml X 1000 

= 15.44 M 

please mark mine as the brainliest answer