Question

calculate the molarity of each of the following (a) 30g of Co(No)3.6H2O in 4.3L of solution (b) 30mL of 0.5M H2So4 diluted to 500ml​

Answer 1

Answer:

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Explanation:

Molarity is given by:

Molarity = moles of solute / Volume of solution in litre

(a) Molar mass of Co(NO3)2.6H2O

= 59 + 2 (14 + 3 × 16) + 6 × 18 = 291 g mol - 1

∴Moles of Co(NO3)2.6H2O = 30 / 291 mol

= 0.103 mol

Therefore, molarity = 0.103 mol / 4.3 L

= 0.023 M

(b) Number of moles present in 1000 mL of 0.5 M H2SO4 = 0.5 mol

∴ Number of moles present in 30 mL of 0.5 M H2SO4 = (0.5 X 30 ) / 1000 mol

= 0.015 mol

Therefore, molarity = 0.015 mol / 0.5 L

= 0.03 M

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