Calculate the molarity of h2 s o4 in which mole fraction is 0.85
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Answer:Molality of H2SO4=?
n1= number of moles of H2O and n2= number of moles of H2SO4 .
Molality of H2SO4 means the number of moles of H2SO4 present in 1000g of water
g.mol wt of water (H2O)=2×1)+16=18g
Mole fraction of H2O in solution =0.85
Mole fraction of H2SO4 in solution =1−0.85=0.15
n1 = no of moles of H2O
=wt.of.H2Og.mol.wt.ofH2O
=100018
=55.55
n2 = no of moles of H2SO4=?
Mole fraction of H2SO4=n2n1+n2
0.15=n255.55+n2
or 0.15(55.55+n2)=n2
or n20.15n2+8.3325
n2=9.8
Molality =9.8 m
or Molality of H2SO4=xH2SO4xH2O×1Mol.wt.ofH2O×1000
=1−0.850.85
0.15×118×1000=9.8m
Explanation:
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