Question

calculate the molarity of h2so4 solution containing 4.9g of h2so4 per litre of the solutuon.​

Answer 1

Answer:

mols = 4.9/98 = 0.05. You have 0.05 mols/L - 0.05 M

Answer 2

Mass of solute in 100ml of solution = 90 g of H2SO4

Moles = Mass of solute in 100ml in solution = 90 = 0.9183. Molar mass 98.

Volume = mass X density.

Wt of 100ml of solution = 100 X 1.8 = 180 g.

Solution = solvent + solute.

180= x + 90.

x = 180 -90 = 90 g.

Molarity = No.

Here is the method :-

Molarity of sulfuric acid solution is 0.0499 mol/L.

Hope its help u :-