calculate the molarity of HNO3 dissolved in 250 ml. aqueous solution
Answers
Explanation:
The number of moles of nitric acid can be obtained by multiplying the molarity with volume
M×V=Moles of HNO
3
=
1000
250×2
=0.5
The mass of nitric acid can be obtained by multiplying the number of mols with molar mass and dividing with percentage concentration.
∴HNO
3
required =0.5×63×
70
100
=45g
Thus 45.0 g conc. HNO
3
of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO
3
.
Answer:
12th
Chemistry
The p-Block Elements
Nitric Acid
How many grams of concentra...
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Asked on October 15, 2019 by
Priyam Yasmin
How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO
3
? The concentrated acid is 70% HNO
3
.
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ANSWER
The number of moles of nitric acid can be obtained by multiplying the molarity with volume
M×V=Moles of HNO
3
=
1000
250×2
=0.5
The mass of nitric acid can be obtained by multiplying the number of mols with molar mass and dividing with percentage concentration.
∴HNO
3
required =0.5×63×
70
100
=45g
Thus 45.0 g conc. HNO
3
of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO
3
.