calculate the molarity of KoH in the solution prepared by dissolving its 10g in enough water to form 750 ml of solution
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volume of solution= 0.75 litres
molar mass of KOH = 39 + 16 + 1 => 56 grams per mole.
Hence, 10 grams is 10/56 => 0.178 moles (approx.)
molarity = (moles of solute)/litres of solution
=> 0.178/0.75 => 0.237 M
Hence, the molarity of the solution is 0.24 M (molar) approximately.
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