Question

Calculate the molarity of
molarity of the solution if
Naoh is present in 100 ml aqueous solution​

Answer 1

ANSWER

Moles of NaOH =

40

16

=0.4

Density = 1.06 g/ml

1ml weighs 1.06 gms

100 ml solution weighs

1

1.06

×100=106gms

Therefore, amount of solvent = 106 − 16 = 90 gms

Moles of solvent =

18

90

=5

Now,

X

sol

= Mole fraction of solute

=

Moles of solute+moles of solvent

Moles of solute

X

sol

=

0.4+5

0.4

=

27

2

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