Calculate the molarity of Na2SO3. in the solution prepared by dissolving its 16g in enough water in from 700ml of the solution. answer this
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Answer:number of moles of Na2SO3÷700×1000 is your answer
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Ok so we know
Molarity = no. of moles/vol. of solution
So we first calculate no. Of moles of Na2SO3 we have,
n = given mass/ Molar mass
= 16g/126g
Vol. Of solution = 700/1000 L
Putting in the formula
M = 16 x 1000/(126 x 700)
= 0.18 approx
The calculation part is not good i know .. but if u r aware of the formula it's very easy to solve.. ask for doubts if any
I hope it helps..
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