Question

Calculate the molarity of NaOH in the solution prepared by dissolving its 4g in enough water to form 250ml of the solution.​

Answer 1

Explanation:

We know that

$\boxed{\sf Molarity(M)=\dfrac{No\:of\:moles\:of\:solute}{Volume\:of\:solution\;in\:litres}}$

$\\ \rm{:}\longrightarrow \dfrac{Mass\:of\:NaOH/Molar\:mass\;of\:NaOH}{0.250L}$

$\\ \rm{:}\longrightarrow \dfrac{0.1mol}{0.250L}$

$\\ \rm{:}\longrightarrow 0.4molL^{-1}$

$\\ \rm{:}\longrightarrow 0.4M$

Answer 2

$\huge\tt{\bold{\purple{\underbrace{\red{\mathfrak{Answer♡༄}}}}}}$

$Weight \: of  \: NaOH \: \longrightarrow \: 4g \\ \\ </p><p></p><p>Molecular \: weight \: of  \: NaOH \longrightarrow40G \\ \\ </p><p></p><p>Volume \: of \: solution \: is \:  250ml \\ \\ </p><p>Molarity \longrightarrow? \\ \\ </p><p>M \longrightarrow \frac{M}{MW} \times \frac{1000}{Vinml} \\ \\ </p><p></p><p></p><p></p><p>M \longrightarrow \frac{4}{40} \times \frac{1000}{250} \\ \\ </p><p></p><p> \huge \boxed {0.4M }</p><p></p><p>$