Question

Calculate the molarity of Oxalic acid solution, if 6.3g of crystalline oxalic acid is dissolved in 250 ml solution.​

Answer 1

We can get the answer using the formula.

N1V1=N2V2 ie. Principle of neutralization.

Here.

Oxalic acid is a dibasic acid as it can release two H+

Hence Molarity = (6.3 x 1000)/( 126 x 250) = 0.2.

=> normality = 0.2 x 2 = 0.4.

For req volume of NaOH.

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