Calculate the molarity of sodium carbonate,2.62of which are dissolved in 600 ml of solution
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Answered by
5
Answer:
NaCo³(molar mass...83gmol')
mole..2.63g/83gmol'
..1.031mol
(m)..1.031/600ml..0.0017molml'
0.0017molml'/1000mll'..1.7molL
Answered by
2
Explanation:
the molar mass of Na2CO3 = 23*2 +12+16*3
= 46+12+48
= 106gmol
Now, = 2.62g/ 106gmol
= 0.024 mol
we know that,
M= no. of moles of solute/volume of the solution in litre
= 0.024 mol * 1000 mL/ 600 mL
= 0.04 moL L
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