Calculate the molarity of solution containing 0.5g of NaoH (Sodium Hydroxide) desolved in 500 cubic cm?
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Answer:
1 mol NaOH = atomic mass of Na + atomic mass of O + atomic mass of H = 23 + 16 + 1 = 40g.
0.5 g NaOH = 0.5 / 40 mol NaOH = 0.0125 mol of NaOH
500 ml of water = 500/1000 = 0.5 L
Now, molarity = number of moles of solute / total volume of the solvent
= 0.0125 / 0.5 = 0.025 mol/L.
PS: Easy peasy, lemon squeezy!
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