calculate the molarity of solution containing 15 gm of the urea present in 300 ml of solution
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Answer:
molality =
molar mass of urea × mass of water in kg
mass of urea
molality =
60 g/mol× 0.150 kg
15.20 g
molality = 1.689 mol/kg
Hence, option A is correct.
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refer the attachment .... ....
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