Question

Calculate the molarity of solution containing 16 grams Glucose (Molecular Mass=180) per 300 ml solution.

Answer 1

Answer:

1.Molarity = moles of solute/liters of solution = mol/L.

2.Calculate moles (n) of glucose (C₆H₁₂O₆) from its mass (m) and molar mass (M).

3.M(C₆H₁₂O₆) = (6⨯12g/mol C) + (12⨯1g/mol H) + (6⨯16g/mol O) = 180 g C₆H₁₂O₆/mol C₆H₁₂O₆

4.n(C₆H₁₂O₆) = 16 g C₆H₁₂O₆ ⨯ 1mol C₆H₁₂O₆/180 g C₆H₁₂O₆ = 0.0888889 mol C₆H₁₂O₆