Question

calculate the molarity of solution containing 4 Gram of sodium hydroxide NaOH in 100ml ​

Answer 1

Answer:

N=w×1000eq.wt.×Volume in ml.=4×100040×100=1.0N.

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Answer 2

Answer:-

Molar mass of NaOH:-

$\\ \sf\longmapsto 23u+16u+1u$

$\\ \sf\longmapsto 40u=40g$

Now

$\\ \sf\longmapsto 4g\:of\:NaOH=\dfrac{4}{40}mole\:of\:NaOH=0.1mol\: NaOH$

• Volume of solution=100ml=0.1litre

We know

$\boxed{\sf Molarity=\dfrac{Mole\:of\:Solute}{Volume\:of\:solution\:in\;litre}}$

$\\ \sf\longmapsto Molarity=\dfrac{0.1}{0.1}$

$\\ \sf\longmapsto Molarity=1M$