Question

Calculate the molarity of solution containing 40 g. Of glucose ( C6H12O6 ) in 350 ml. Of solution.
( at wt. C=12, H=1, O= 16)​

Answer 1

Answer:

mass of solute = 40g

molar mass of glucose = 180u

moles = 40 ÷ 180 = 0.22 mol

molarity = 0.22 × 1000

350

= 0.628