Question

Calculate the molarity of solution containing 9.8gram of H2SO4 per 300ml solution

Answer 1

Answer:

The molarity of a solution is 0.5 mol/L.

Mass of sulfuric acid = 9.8 g

Volume of the solution = 200 mL = 0.2 L

Molarity:

\frac{\text{Mass of}H_2SO_4}{\text{molar mass of}H_2SO_4\times \text{Volume of the solution (L)}}

molar mass ofH

2

SO

4

×Volume of the solution (L)

Mass ofH

2

SO

4

Molarity=\frac{9.8 g}{98 g/mol\times 0.2 L}=0.5 mol/LMolarity=

98g/mol×0.2L

9.8g

=0.5mol/L

The molarity of a solution is 0.5 mol/L.

Answer 2

Answer:

9.8% (w/w) of H

2

SO

4

solution means 9.8 g of solute in 100 g of solution.

Density of H

2

SO

4

=1.2 g/ml

The volume of the solution =

Density

Mass

=

1.2

100

=83.33ml

Molarity =

98×83.33

9.8×1000

=1.2 M