Question

calculate the molarity of solution of Ethanol in water in which the mole fraction of Ethanol is 0.040​

Answer 1

Answer:

Explanation:

Moles of ethanol = 0.04 mol

Moles of water = 1 - 0.04 = 0.96 mol

Mass of ethanol = 0.04 mol x 46 g/mol = 1.84 g

Mass of water = 0.96 mol x 18 g /mol = 17.3 g

Mass of the solution = 17.3 g + 1.84 g = 19.1 g

Assuming density of water to be 1 g/ml,

Volume of solution = mass / density = 19.1 / 1 = 19.1 ml = 0.0191 L

Molarity is the number of moles of solute present in 1 L of solution.

Hence,

Molarity of the solution = 0.040 / 0.0191 = 2.1 M