Calculate the molarity of the 10% HNO3 solution having density 1.02g/cc
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density = 1.02 g/cc
=>Let volume of solution be 1 litres.
Given, the concentration of HNO3 is 10% ,
10/100 X 1000 ml =>100 ml =>0.1 L of HNO3 is present.
1 L - 0.1 L of water is present => 0.9 L of water is present.
mass of HNO3 present= density X volume => 1.02 X 100 grams =>102 g
molar mass of HNO3 is 1+14+48 => 63 grams per mole.
Hence, 102 grams of HNO3 is 102/63 => 1.619 moles of HNO3.
Volume of solution = 1 L
molarity = (moles of HNO3) /(litres of solution) =>1.619/1 => 1.62 M
Hence, molarity of 10% HNO3 solution is 1.62 M
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