calculate the molarity of the 10 Percent aqous solution of h2so4 density of the solution is 1.4g per milliliter
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An aq solution of H2SO4 10percent by volume means that- 10 ml acid in 100 ml solution
Thus volume of H2SO4= 10ml
Volume of water= 90 ml
Density of solution is 1.2 g/cc
Thus mass of solution=volume*density= 1.2*100
Mass of solution is=120g
Mass of water= 90*1 = 90g
Mass of solute= 120-90 = 30g
Molality is moles of solute divided by mass of solvent in kg
Hence molality= (30/98*1000/90) molal
Hope it helps:)
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