Chemistry, asked by ak260339p1m1fd, 1 year ago

Calculate the molarity of the 3m aq. solution of NaCl of density 1.25 g ml-1. ​

Answers

Answered by stew123
2

Molality is 3m ie 3 moles of NaCl in 1000g of water(solvent)

Density of solution = 1.25g/ml

Mass of NaCl = moles x molar mass = 3 x 58.5 = 175.5g

Mass of solution = mass of solute + mass of solvent = 175.5 + 1000 = 1175.5g

Volume of solution = Mass/Density = 1175.5/1.25 = 940.4ml

Molarity = 3/0.9 = 3.33 mol/L

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