Calculate the molarity of the 3m aq. solution of NaCl of density 1.25 g ml-1.
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Molality is 3m ie 3 moles of NaCl in 1000g of water(solvent)
Density of solution = 1.25g/ml
Mass of NaCl = moles x molar mass = 3 x 58.5 = 175.5g
Mass of solution = mass of solute + mass of solvent = 175.5 + 1000 = 1175.5g
Volume of solution = Mass/Density = 1175.5/1.25 = 940.4ml
Molarity = 3/0.9 = 3.33 mol/L
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