Question

Calculate the molarity of the 3m aq. solution of NaCl of density 1.25 g ml-1. ​

Answer 1

Answer:

3.18 M

Explanation:

$molality = 1000 \times molarity \div 1000 \times density - molarity \times molecular \: mass \: of \: substance$

by putting the values in the formula we can get the value of molarity i.e., 3.18