Question

calculate the molarity of the solution 6gm of sodium carbonate present in a 450 ml of given solution....​

Answer 1

Answer:

Molecular mass of Na2CO3=106 gmol−1

∴ Number of moles =10653=0.05mol

As 0.05 mol are dissolved in 500mL;

Number of moles dissolved in 1000mL (1L) or molarity of th solution

=5000.05×1000=0.1M.

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