Chemistry, asked by tanishaRahman, 1 month ago

calculate the molarity of the solution when
1.8g glucose is dissolved in 1500me of H2O​

Answers

Answered by Anonymous
0

Answer:

15% glucose C

6

H

12

O

6

in H

2

O

15g of glucose in 85g of H

2

O

Solute⟶glucose⟶15g

Solvent⟶H

2

O⟶85g

No. of moles of solute=

MolarMass

GivenMass

Molar Mass of C

6

H

12

O

6

= 6x12+12x1+6x16

= 72+12+96=180

n=

180

15

=0.0833

Density⟶1.5g/mL

1.5g⟶1mL

1g⟶

1.5

1

mL

100g⟶

1.5

1

×100mL

1.5

100

mLofsolution

1.5

100

×

1000

1

Lofsolution

15

1

Lofsolution

Molarity=

Volume of solution in L

Moles of solute

=

1/15

15/180

=

180

15

×

1

15

=1.25M

Molality=

Mass of solvent in kg

Moles of solute

=

85/1000

15/180

=

180

15

×

85

1000

=

51

50

=0.980m

Molarity of solution=1.25M

Molality of solution=0.980m

Explanation:

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Answered by shrutikhot
0

Answer:

.x330 \times  {312 {31 \times  { \times . {343 =  =  =  \times  \times  \times  { =  \times \frac{?}{?} }^{2} }^{?} }^{?} }^{?} }^{?}

Explanation:

11 { {1 {12 \times  - 11}^{?} }^{?} }^{2}

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