Question

calculate the molarity when 7.3 gram HCL is dissolved is 29.5 dm3 of water (H=1,CL=36.5)​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

Calculate the molarity when 7.3 gram HCl is dissolved is 29.5 dm³ of water

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Mass of HCl = 7.3 gram
• Volume of Solution ( V ) = 29.5dm³

$\large\underline{\underline{\sf To\:Find:}}$

• Molarity .

Molecular Mass of HCl ➝

➝ 1 + 35.5

➝ 36.5

Mole of HCl ➝

✪$\large{\boxed{\bf \blue{Mole(n)=\dfrac{Mass}{Molecular\:Mass}}}}$

$\implies{\sf n = \dfrac{7.3}{36.5} }$

$\implies{\sf \green{n=0.2} }$

Molarity ➝

✪${\boxed{\bf \blue{Molarity=\dfrac{Mole\:of\: Solute}{Volume\: of\: Solution(in\:litre)}} }}$

$\large\underline{\underline{\bf REMEMBER-}}$

${\boxed{\sf \red{1\:dm^3=1L}}}$

$\implies{\sf M = \dfrac{0.2}{29.5} }$

$\implies{\sf \red{Molarity (M)=6×10^{-3}} }$

$\huge\underline{\underline{\bf \orange{Answer}}}$

Molarity is ${\bf \red{6×10^{-3}}}$