Question

Calculate the mole fraction, molarity and molality of nh3 if it is in a solution composed of 30.6 g nh3 in 81.3 g of h2o. the density of the solution is 0.982 g/ml and the density of water is 1.00 g/ml.

Answer 1

Answer:

Explanation:

molarity = $\frac{moles of solute}{volume of solution}$

molarity = $\frac{30.6 .g}{17.01 .g mol^{-1} }\\\frac{30.6 +81.3 .g}{0.982 .g mL^{-1} }$

molarity = $\frac{mole of solute}{kilogram of solvent}$

= $\frac{\frac{30.6 .g}{17.01 .g mol^{-1} } }{81.3 * 10^{-3} .kg }$         =    $\frac{1.80 .mol}{0.114 . L}$          =  22.1 .mol .kg