Chemistry, asked by fidashajahan, 6 months ago

calculate the mole fraction of 25g ethylene glycol (C2H6O) in 75g of Benzene

Answers

Answered by akulanagalakshmi6957

0

answer is 18g/mol

Explanation:

2200 grams C2H6O in 100g sol

M2(C2H6O2)=12×2+6×1+16×2=62/mol

W2=20g

W1(H2O)=100g-20g=80g

M1(H2O)=2×1+16×1

=18g/mol

therefore n1=w1/M1=80/18=4.444mol

n2=W2/M1=20/62=0.322mol

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