Question

Calculate the mole fraction of a solute in a solution containing 18g of glocuse in 100g of water

Answer 1

Given:-

→ Mass of glucose (solute) = 18g

→ Mass of water (solvent) = 100g

To find:-

→ Mole fraction of solute

Solution:-

Molar mass of glucose [C₆H₁₂O₆] :-

= 12×6+1×12+16×6

= 72+12+96

= 180g

Molar mass of water [H₂O]

= 1×2+16

= 18g

Moles of solute:-

= Given Mass/Molar mass

= 18/180

= 0.1 mole

Moles of solvent:-

= Given Mass/Molar mass

= 100/18

= 5.55 moles

Mole fraction of a solute:-

= Moles of solute/Total moles in soluⁿ

= 0.1/[0.1+5.55]

= 0.1/5.65

= 0.017 [approximately]

Thus, mole fraction of the solute

is 0.017.

Answer 2

Answer:

hiiiiiiiiiiiiiiiiii.........