Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride
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ExplainaTion:
•Suppose the mass of the solution =
100g.
•So, mass of C6H6=
30g
• mass ofCCl4=
100−30=70g.
•nC6H6=massmolecular mass
=30g78/mol=0.385mol
•Similary , nCl4=70g/154g/mol
=0.455mol.
•xC6H6=nC6H6nC6H6+nCCl4=
0.3850.385+0.455
•=0.458xCCl4
=1−0.458
= 0.542
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