Question

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

Answer 1

Answer:

0.458

Explanation:

Let the total mass of the solution be 100 g and the mass of benzene be 30g

∴ Mass of carbon tetrachloride = (100 - 30)g = 70 g

Molar mass of benzene (C6H6) = (6 × 12 + 6 × 1) g mol - 1

= 78 g mol - 1

∴ Number of moles of C6H6  =30/78 mol

= 0.3846 mol

Molar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 35.5

= 154 g mol - 1

∴ Number of moles of CCl4 = 70/154 mol

= 0.4545 mol

Thus, the mole fraction of C6H6 is given as:

= 0.3846 / (0.3846 +0.4545)

= 0.458

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Answer 2

Answer:

Let the mass of solution be 100 gm

Mass of Benzene =30 gm

Mass of CCl

4

=70 gm

Moles of Benzene =

78

30

=0.385

Moles of CCl

4

=

154

70

=0.45 moles

Mole fraction (Benzene) =

0.385+0.45

0.385

=0.461