Question

calculate the mole fraction of c6h6o2 in a solution containing 20% of c6h6o2

Answer 1

Explanation:

Let total mass of solution =100g

∴ mass of ethylene glycol W2=20g

Mass of solvent (water) W1=80g

Molar mass of [C2H6O2]M1=12×2+6×16×2

⇒24+6+32

⇒62gmol−1

Molar mass of water (H2O)M2=1×2+16

⇒18gmol−1

Molar of water n1=W1M1=8018=4.44 mole

Moles of C2H6O2,

n2=W2M2=2062

⇒0.322 mol

Mole fraction of C2H6O2=n2n1+n2

⇒0.3224.44+0.322

⇒0.068