Question

calculate the mole fraction of each compound of solution containing 15g of acetic acid (molar mass 60g) in 72g of water (molar mass 14)​

Answer 1

Molar mass of acetic acid - 60 g

it's given mass-15 g

no. of moles of acetic acid-15/60=0.25moles

molar mass of water -18g

it's mass given-72g

it no. of moles- 72/18=4 moles

no of mole of solution=4.25

mole fraction=moles of acetic acid/moles of solution

=0.25/4.25=1/17

ans- 1/17