Question

calculate the mole fraction of ethanol and water in a solution which is 46 gram of ethyl alcohol and 90 gram of water has been mixed

Answer 1

molecular mass of C2H6O (ethanol) = 46amu
molecular mass of H2O = 18amu

no. of moles = given mass/molecular mass

therefore, no. of moles of ethyl alcohol (ethanol) = 46/(molecular mass of C2H6O)
= 46/4
= 1 moles
no.of moles of H2O=90/(molecular mass of H20)
=90/18
= 5 moles

total moles = moles of ethanol + moles of H2O
= 1+5=6 moles

mole fraction of sub.= moles of sub./total moles
mole fraction of ethanol= 1/6
=0.1666

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Answer 2

Answer:

0.09

Explanation:

Molecular mass of C2H6O (ethanol) = 46amu

molecular mass of H2O = 18amu

no. of moles = given mass/molecular mass

therefore, no. of moles of ethyl alcohol (ethanol) = 46/(molecular mass of C2H6O)

= 46/4

= 1 moles

no.of moles of H2O=90/(molecular mass of H20)

=90/18

= 5 moles

total moles = moles of ethanol + moles of H2O

= 1+5=6 moles

mole fraction of sub.= moles of sub./total moles

mole fraction of ethanol= 1/6

=0.1666

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