calculate the mole fraction of ethanol if 46g ethanol present in 36g of water
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Ethanol = C2H5OH
molecular mass = 24 + 5 + 16 +5 = 50
moles of Ethanol = 23/50
moles of water = 36/18 = 2 moles
now mole fraction of ethanol = (23/50) / (23/50 + 2)
= 23/123
molecular mass = 24 + 5 + 16 +5 = 50
moles of Ethanol = 23/50
moles of water = 36/18 = 2 moles
now mole fraction of ethanol = (23/50) / (23/50 + 2)
= 23/123
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